wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The equation a8X8+a7X7+a6X6++a0=0 has all its roots positive and real (where a8=1,a7=4,a0=128), then which of the following is/are true?

A
a1=128
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a1=124
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a2=724
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
a3=122
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct options are
B a1=124
C a2=724
Let the roots be α1, α2,α8. then,
α1, α2,α8=4 α1α2α8=128 (α1α2α8)18=12
=α1+α2++α88=(α1α2α8)18
AM=GM all the roots are equal 12
a1=8C7(12)7=124 a2=8C6(12)6=724 and a3=8C5(12)5

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Relation of Roots and Coefficients
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon