The factorisation of $x^{2} - 5 x + 6$ is

(x - 3) (x + 2)

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(x + 3) (x + 2)

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(x + 3) (x - 2)

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(x - 3) (x - 2)

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Solution

The correct option is D $(x - 3) (x - 2)$
The given expression is
$x^{2} - 5 x + 6$
The product of first and last term is $6 x^{2}$ .
The middle term is -5x.
So, two terms whose product is $6 x^{2}$ and sum is $- 5 x$ will be
$- 3 x a n d - 2 x$
So, the expression can be written as
$x^{2} - 3 x - 2 x + 6$
= $x (x - 3) - 2 (x - 3)$
= $(x - 3) (x - 2)$ [Taking (x-3) common]

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