The factors of $15 x^{2} - 26 x + 8$ are _______.

(3 x - 4) (5 x + 2)

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(3 x - 4) (5 x - 2)

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(3 x + 4) (5 x - 2)

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(3 x + 4) (5 x + 2)

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Solution

The correct option is C $(3 x - 4) (5 x - 2)$
$G i v e n : 15 x^{2} - 26 x + 8$

If an equation $a x^{2} + b x + c$ is to be factorised,
$S t e p I :$ Calculate $a \times c$
$S t e p I I :$ Divide $b$ as sum of two numbers such that their product equals $a \times c$

Here,
$a = 15$
$| b | = 26$
$c = 8$

$a \times c = 120 = 20 \times 6$
Also, $20 + 6 = 26$

By this,
We can write given equation as,
$\to 15 x^{2} - 20 x - 6 x + 8$
$\Rightarrow 5 x (3 x - 4) - 2 (3 x - 4)$

$\Rightarrow (5 x - 2) (3 x - 4)$ $∴ A n s w e r$

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