The factors of 22 x 2-77 x are 11 x and 2-7 x -A- TrueB- False

The correct option is B False The expression 22x^2+77x can be written as, =2 × 11 × x × x+7 × 11 × x Taking 11x common, we get =11x(2x+7) ⇒ 22x^2+77x=11x(2x+7 ...

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Byju's Answer

Standard VII

Mathematics

Factors of a Term

The factors o...

Question

The factors of $22 x^{2} + 77 x$ are $11 x$ and $(2 + 7 x)$ .

True

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False

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Solution

The correct option is B
False

The expression $22 x^{2} + 77 x$ can be written as,

$= 2 \times 11 \times x \times x + 7 \times 11 \times x$

Taking $11 x$ common, we get

$= 11 x (2 x + 7)$

$\Rightarrow$ $22 x^{2} + 77 x$ = $11 x (2 x + 7)$

Therefore, the factors of $22 x^{2} + 77 x$ are $11 x$ and $(2 x + 7)$ .

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The factors of 22x2+77x are 11x and (2+7x).

The correct option is B False The expression 22x2+77x can be written as, =2×11×x×x+7×11×x Taking 11x common, we get =11x(2x+7) ⇒ 22x2+77x=11x(2x+7) Therefore, the factors of 22x2+77x are 11x and (2x+7).

The factors of $22 x^{2} + 77 x$ are $11 x$ and $(2 + 7 x)$ .