The factors of $(4 x^{3} + 12 x^{2} + 6 x + 18)$ is/are:

None of these

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(4 x^{2} + 6)

(x + 3)

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(x + 2)

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(2 x^{2} + 5)

(4 x^{2} + 6)

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Solution

The correct option is B $(4 x^{2} + 6)$ $(x + 3)$
$4 x^{3} + 12 x^{2} + 6 x + 18 = 4 x^{2} (x + 3) + 6 (x + 3) = (x + 3) (4 x^{2} + 6)$

Therefore, option (b) is the correct answer.

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Question :

One of the factors of x⁵+x+1 is

(1) 2x² - x - 1

(2) x³ - x²+ 1

(3) x² - 2x² + 1

(4) x³ + x² + 1

x^{3} + 9 x^{2} - 6 x - 4

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