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Question

the factors of x37x+6 are


A

x9x6(x1)

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B

(x26)(x1)

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C

(x+1)(x+2)(x3)

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D

(x1)(x+3)(x2)

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Solution

The correct option is D

(x1)(x+3)(x2)


x37x+6=x317x+7=(x1)(x2+x+1)7(x1)=(x1)(x2+x+17)=(x1)(x2+x6)=(x1)[x2+3x2x6]=(x1)[x(x+3)2(x+3)]=(x1)(x+3)(x2)


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