The floor of a room is to be decorated with square tiles of length $6$ m. How many tiles are required if the floor of the room has dimensions $36 m \times 24 m$ ?

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Solution

Area of floor = $36 \times 24 = 864$ sq. m
Area of one tile = $6 \times 6 = 36$ sq. m.
Therefore,
Tiles required = $\frac{864}{36} = 24$ tiles

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The floor of a room is to be decorated with square tiles of length 6m. How many tiles are required if the floor of the room has dimensions 36 m×24 m ?

Area of floor = 36×24=864 sq. mArea of one tile = 6×6=36 sq. m.Therefore,Tiles required = 86436=24 tiles

The floor of a room is to be decorated with square tiles of length $6$ m. How many tiles are required if the floor of the room has dimensions $36 m \times 24 m$ ?

Area of floor = $36 \times 24 = 864$ sq. m
Area of one tile = $6 \times 6 = 36$ sq. m.
Therefore,
Tiles required = $\frac{864}{36} = 24$ tiles