Question

The formation of molecular complex $B{F}_3-N{H}_3$ results in a change in hybridisation of boron:

• A. From $s{p}^3\text{to}s{p}^{3}d$
• B. From $s{p}^2\text{to}ds{p}^2$
• C. From $s{p}^3\text{to}s{p}^2$
• D. From $s{p}^2\text{to}s{p}^3$

Answer 1

The correct option is D From $s{p}^2\text{to}s{p}^3$

In $B{F}_3$, boron atom has $3$ bond pairs of electrons and $0$ lone pairs of electrons. It is $s{p}^2$ hybridized. In $B{F}_3-N{H}_3$, boron atom has $4$ bond pairs of electrons and $0$ lone pairs of electrons. It is $s{p}^3$ hybridized. So the formation of molecular complex results in a change in hybridization of boron from $s{p}^2\text{to}s{p}^3$.