The GCD of $15 x^{4} y^{3} z^{5}, 12 x^{2} y^{7} z^{2}$ is:

$3 x^{2} y^{3} z^{2}$

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$3 x^{3} y^{3} z^{3}$

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$3 x^{4} y^{4} z^{2}$

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$3 x y z^{2}$

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Solution

The correct option is A
$3 x^{2} y^{3} z^{2}$

Given,
$15 x^{4} y^{3} z^{5} a n d 12 x^{2} y^{7} z^{2}$
Here, the common divisros of the given experssions are:
$3, x^{2}, y^{3}$ and $z^{2}$ .
Therefore, GCD $= 3 \times x^{2} \times y^{3} \times z^{2} = 3 x^{2} y^{3} z^{2}$

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