The histogram for the following
Class Marks2535455565Frequency71518128
As the difference between the values of the consecutive class mark is 10,
therefore subtract 102=5 from each class mark to get the lower limit
and add 5 to each class mark to get the upper limit.
Thus, the given frequency distribution will be of the form
CIFrequency20−30730−401540−501850−601260−708