The length of $M^{'} N^{'},$ if $M N = 8 c m$ .

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Solution

$△$ LMN is reduced to L'M'N' by 0.8
Hence. $\frac{M^{'} N^{'}}{M N} = 0.8$
$\frac{M^{'} N^{'}}{8} = 0.8$
$M^{'} N^{'} = 8 \times 0.8$
$M^{'} N^{'} = 6.4$ cm

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The length of M′N′, if MN=8 cm.

△ LMN is reduced to L'M'N' by 0.8Hence. M′N′MN=0.8M′N′8=0.8M′N′=8×0.8M′N′=6.4 cm

The length of $M^{'} N^{'},$ if $M N = 8 c m$ .

$△$ LMN is reduced to L'M'N' by 0.8
Hence. $\frac{M^{'} N^{'}}{M N} = 0.8$
$\frac{M^{'} N^{'}}{8} = 0.8$
$M^{'} N^{'} = 8 \times 0.8$
$M^{'} N^{'} = 6.4$ cm