Question

The Lewis dot structure of beryllium fluoride molecule is:

• A.
• B.
• C.
• D.

Answer 1

The correct option is D

In a lewis dot structure the inner shell electrons and the nucleus of the atom is represented using the symbol of the element. While, the valence electrons are represented as dots around the symbol.

Electronic configuration of beryllium atom is $1s^2$ $2s^2$. It has two electrons in the valence orbit(second orbit).

Fluorine has an electronic configuration of $1s^2$ $2s^2$ $2p^6$ $3s^2$ $3p^5$. It has seven electrons in it's valence orbit (third orbit).

The beryllium atom shares one electron with each fluorine to form the beryllium flouride molecule. Thus, the lewis dot structure of beryllium flouride is: