The magnitude of i in ampere unit is
Applying Kirchoff's law in following figure.
At junction A:
i+i1+i2=1 ....(i)
For loop (i)
−60i+(15+5)i1 = 0
⇒ i1=3i ....(ii)
For loop (2)
−(15+5)i1+10 i2=0
⇒ i2=i1=(3 i)
On solving equation (i),(ii) and (iii) we get i=0.1 A
Short Trick: Branch current = main current (Resistance of opposite branchTotal resistance)
⇒ i=1×[203203+60]
=0.1 A