The mean of $6$ , $y$ , $7$ , $x$ and $14$ is $8$ ,then

x + y = 13

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x - y = 13

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2 x + 3 y = 13

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x^{2} + y^{2} = 15

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Solution

The correct option is A $x + y = 13$
Given: Mean of $6, y, 7, x, 14$ is $8$
Mean = $\frac{s u m}{n u m b e r o f o b s e r v a t i o n s}$
$8 = \frac{6 + y + 7 + x + 14}{5}$
$40 = x + y + 27$
$x + y = 13$

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