MyQuestionIcon

1

You visited us 1 times! Enjoying our articles? Unlock Full Access!

Analgesics

The molarity ...

Question

The molarity of a sulphuric acid sample havingdensity 2.12 g/mL and mass percentage 49% (w/w)is equal to(1) 18.8 M() 16.8 M(3) 10.6 M(4) 21.1 M

Open in App

Solution

Suggest Corrections

thumbs-up

4

Similar questions

Q. The molarity of

H N O_{3}

in a sample which has density 1.4 g/mL and mass percentage of 63% is (Molecular weight of

H N O_{3} = 63) .

Q. Calculate the mass percent (w/w) of sulphuric acid in a solution prepared by dissolving

4

g of sulphur trioxide in a

100

ml sulphuric acid solution containing

80

mass percent (w/w) of

H_{2} S O_{4}

and having a density of

1.96 g / m l

(molecular weight of

H_{2} S O_{4} = 98

) Take reaction

S O_{3} + H_{2} O \to H_{2} S O_{4}

.

Q. If mass by volume percentage of sulphuric acid is 24.5% then the molarity of sulphuric acid solution is:

49 g of sulphuric acid are dissolved in 250 ml of the solution. Its molarity will be

Q. In a sample of sodium carbonate some sodium sulphate is also mixed.

1.25 g

of this sample is dissolved and the volume made up to

250 m L

25 m L

of this solution neutralises

20 m L

\frac{N}{10}

sulphuric acid. Calculate the percentage of sodium carbonate in the sample.

View More

Join BYJU'S Learning Program

similar_icon

Related Videos

lock

Neurologically Active Drugs

CHEMISTRY

Watch in App

explore_more_icon

Explore more

Standard XII Chemistry

Join BYJU'S Learning Program

CrossIcon