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Question

The normal at 3 points P,Q,R on y2=4ax meet at a point N. If S is focus of parabola then the value ofSP+SQ+SR+SAMN is
(where A is vertex of parabola M is the foot of perpendicular from N on to tangent at vertex)

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Solution

Let N=(h,k)
Normal is y=tx+2at+at3.
It is passing through (h,k)
k=th+2at+at3
at3+(2ah)tk=0
It has 3 roots t1,t2,t3
t1+t2+t3=0...(i)
t1t2+t2t3+t3t1=2aha...(ii)
t1t2t3=ka...(iii)
Now P=(at21,2at1), Q(at22,2at2), R(at23,2at3)
S=(a,0), A(0,0), M=(0,k),N=(h,k)
Now,
SP+SQ+SR+SAMN=a+at21+a+at22+a+at23+ah
=4a+a(t21+t22+t23)h
=4a+a{(t1+t2+t3)22(t1t2+t2t3+t3t1)}h
Putting values from (i) and (ii), we get
SP+SQ+SR+SAMN=2

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