Question

The number of ions formed, when bis ( ethane $-$1, 2 $-$ diamine ) copper ( II ) sulphate is dissolved in water is:

• A. 1
• B. 2
• C. 3
• D. 4

Answer 1

The correct option is B 2

bis(ethane-1,2-diamine)copper(II)sulphate

$\left[Co\right(en{)}_2\left]\right(S{O}_4)⟶{\left[Co\right(en{)}_2]}^{2^{+}}+(S{O}_4{)}^{2_{-}}$

It gives two ions, one complex ion and one sulphate ion).