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Question

The number of solutions of the equation x+2tanx=π2 in the interval [0, 2π] is :

A
5
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B
2
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C
4
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D
3
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Solution

The correct option is D 3
x+2tanx=π2 in [0, 2π]
2tanx=π2x
tanx=π4x2
y=tanx and y=x2+π4


From the above graph it can be observed that there are 3 intersection points in [0, 2π]
Number of solutions =3

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