The points (5, -4, 2) (4, -3, 1), (7, 6, 4) and (8, -7, 5) are the vertices of
none of these
Suppose :
A (5, -4, 2)
B (4, -3, 1)
C (7, 6, 4)
D (8, -7, 5)
AB=√(4−5)2+(−3+4)2+(1−2)2
=√(−1)2+(1)2+(−1)2
=√1+1+1=√3
BC = √(7−4)2+(6+3)2+(4−1)2
=√(3)2+(9)2+(3)2
=√9+81+9=√99=3√11
CD = √(8−7)2+(−7−6)2+(5−4)2
= √(1)2+(−13)2+(1)2
√1+169+1=√171
DA = √(8−5)2+(−7+4)2+(5−2)2
=√(3)2+(−3)2+(3)2
√9+9+9=√27=3√3
We see that none of the sides are equal.