The points A(1,2,−1),B(2,5,−2),C(4,4,−3) and D(3,1,−2) are
A
collinear
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B
vertices of a rectangle
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C
vertices of a square
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D
vertices of a rhombus
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Solution
The correct option is B vertices of a rectangle AB=√(2−1)2+(5−2)2+(−2+1)2 AB=√(1)2+(3)2+(−1)2 AB=√11 Similarly you find that BC=√6 CD=√11 and DA=√6 Hence opposite sides of quadrilateral are equal, Now we check the diagonals AC=√(4−1)2+(4−2)2+(−3+1)2 AC=√17 similarly BD=√17 Diagonals are not equal direction ratio of line passing through AB is (1,3,-1) direction ratio of line passing through BC is (2,-1,-1), As the dot product dr of AB and BC are equal to 0 which means AB is perpendicular to BC,similarly check for others sides too opposite sides are equal and diagonal are equal hence it is rectangle