The points z1=3+√3iandz2=2√3+6i are given on a complex plane. The complex number lying on the bisector of the angle formed by the vector z1 and z2 is
A
z=(3+2√3)2+√3+22i
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B
z=5+5i
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C
z=(3+2√3)2−√3+22i
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D
z=(3+3√3)+2i
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Solution
The correct option is Bz=5+5i Note that z1=3+√3i lies on the line y=(1/√3)xandz2=2√3+6i lies on the line y=√3x
Now from diagram, Equation of angular bisectors will be y=±x Hence from the given options ,z=5+5i will only lie on the bisector of z1 and z2, i.e., y=x.