The product of (6x-4y) and (2x-7y) is

$12 x^{2}$ + $28 y^{2}$ - $50 x y$

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

$12 x^{2}$ + $28 y^{2}$ - $25 x y$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$12 x^{2}$ + $28 y^{2}$ - $100 x y$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

$24 x^{2}$ + $28 y^{2}$ - $50 x y$

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A
$12 x^{2}$ + $28 y^{2}$ - $50 x y$

$(6 x - 4 y) (2 x - 7 y)$

$\Rightarrow$ $12 x^{2}$ - $42 x y - 8 x y$ + $28 y^{2}$

$\Rightarrow$ $12 x^{2}$ + $28 y^{2}$ - $50 x y$

Suggest Corrections

Similar questions

(6 x + 7 y - 4) d x + (7 x - 4 y + 3) d y = 0

Which of the pairs given in options will add up to give $9 x + 5 y$ ?

(7 x - 4 y)

(3 x - 7 y)

Subtract $4 x - 2 y + z$ from the sum of $3 x + 4 y + z$ and $- 6 x + 7 y - 8 z$

$Find the product of (7 x - 4 y) and (3 x - 7 y) .$

Join BYJU'S Learning Program