wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The radial wave function for an orbital in a hydrogen atom is:
ψ=1163(1a0)32[(x1)(x28x+12)]ex2
where, x=2ra0; a0= radius of first Bohr's orbit. The minimum and maximum position of radial nodes from the nucleus are:

A
a0, 3a0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
a02, 3a0
loader
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
C
a02, a0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
a02, 4a0
loader
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B a02, 3a0
At radial node, ψ=0
From given equation,
x1=0 and x28x+12=0
When x1=0
x=1
i.e., 2ra0=1; r=a02 (Minimum)
When x28x+12=0
(x6)(x2)=0
i) x2=0
x=2
2ra0=2, i.e., r=a0 (Middle value)
ii) x6=0
x=6
2ra0=6
r=3a0 (Maximum)

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon
footer-image