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Flux as the Flow

The ratio of ...

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The ratio of electric potential on a equatorial and a axial point of short dipole will be 1 0

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Q. Derive an expression for the potential at a point due to a short dipole. Hence show what will be the potential at an axial and an equatorial point :

Q. The electric potential at a point on the equatorial line of an electric dipole is :

Q. The electric potential at a point situated at a distance r on the axis of a short electric dipole of moment p will be

1 / 4 (π ε_{0})

Q. The electric potential at a point on the equatorial line of an electric dipole is

Q. A short electric dipole has a dipole moment of

16 \times 10^{- 9} C m

. The electric potential due to the dipole at a point at a distance of

0.6 m

from the centre of the dipole, situated on equatorial line is

(\frac{1}{4 π ϵ_{0}} = 9 \times 10^{9} {Nm}^{2} {/C}^{2})

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