The ratio of magnetic dipole moment of an electron of charge e and mass m in the Bohr orbit in hydrogen to the angular momentum of the electron in the orbit is:
A
e/m
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B
e/2m
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C
m/e
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D
2m/e
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Solution
The correct option is B e/2m Magnetic moment μ=IA=(eν)A ∴μ=ev2πR×πR2=evR2 Angular momentum L=mvR Thus μL=evR2mvR=e2m