Question

The reciprocal of $\left(\frac{-3}{8}\right)\times \left(\frac{-7}{13}\right)$ is

Answer 1

Step-1: Solve the given fraction $\left(\frac{-3}{8}\right)\times \left(\frac{-7}{13}\right)$

$\left(\frac{-3}{8}\right)\times \left(\frac{-7}{13}\right)$$=\left(\frac{21}{104}\right)$

Step-2: Find the reciprocal of $\frac{21}{104}$

Reciprocal of $\frac{21}{104}$$=\frac{1}{{\displaystyle \frac{21}{104}}}=1\times \frac{104}{21}=\frac{104}{21}$

Hence, the reciprocal of $\left(\frac{-3}{8}\right)\times \left(\frac{-7}{13}\right)$is $\frac{104}{21}$