Question

The roots of equation $(x-1{)}^3+8=0$ are $-1,1-2\omega ,1-2{\omega }^2$.True or False ?

• A. True
• B. False

Answer 1

The correct option is A True

$(x-1{)}^3+8=0or(x-1{)}^3=-8$
$\therefore x-1=(-8{)}^{1/3}=-2,-2\omega ,-2{\omega }^2$
$Hencex=-1,1-2\omega ,1-2{\omega }^2$