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Question

The roots of the equation 3x+2+3-x = 10 are
(a) 2, 0
(b) −2, 0
(c) 3, −1
(d) −3, 1

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Solution

(b) −2, 0

Given: 3x+2 + 3x = 10Let 3x be equal to y. Then, the equation can be rewritten as: 32 × 3x + 13x = 10 9y + 1y = 109y2 + 1y = 10⇒ 9y2 10y + 1 = 0⇒ 9y2 9y y + 1 = 0 9y(y 1) (y 1) = 0(y 1)(9y 1) = 0y = 1 or y = 19 = 132⇒ 3x = 30 or 3x = 32x = 0 or x = 2

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