The shape of $I F_{6}^{-}$ is :

Trigonally distorted octahedron

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

Pyramidal

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Octachedral

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Square antiprismatic

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A Trigonally distorted octahedron
The shape of $I F_{6}^{-}$ is trigonally distorted octahedron. The central iodine atom has 7 valence electrons. It gains one electron from negative charge. Out of 8 valence electrons, 6 are involved in formation of $6 I - F$ bonds and one lone pair of electrons is present. 6 F atoms are present at 6 corners of distorted octahedron. The lone pair of electrons distorts the octahedral shape.

Suggest Corrections

Similar questions

{I F}_{6}^{+}

I F_{5}

I F_{5}

2 I F_{5} ⇋ I F_{4}^{+} + I F_{6}^{-} .

f (x) = ⎧ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎨ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎪ ⎩ \begin{matrix} a {tan}^{- 1} \frac{1}{x - 4} & , & i f 0 \leq x < 4 \frac{π}{2} & , & i f x = 4 b {tan}^{- 1} \frac{2}{x - 4} & , & i f 4 < x \leq 8 {sin}^{- 1} (7 - x) + \frac{a π}{4} & , & i f 6 \leq x \leq 8 \end{matrix}

a

b

f (x)

[0, 8]

6

6

5

Join BYJU'S Learning Program