The solution set of 2log2log2x+log1/2log2(2√2x)=1 is
{8}
{2,4}
{4,8}
{1/2,4}
log22log2x+log1/2log2(2√2x)=1log2log2x2+log1/2log2(8x)12=1log2log2x2+log1/212+log1/2log28x=1log2log2x2=−log1/2log28xlog2log2x2=log2log28x⇒x2=8x⇒x2−8x=0x(x−8)=0x=8