Question

The solution set of $\frac{3}{x+1}-\frac{2}{x-1}<0$ is

• A. $(-\infty ,-1)\cup (1,5)$
• B. $(-1,1)\cup (5,\infty )$
• C. $(-\infty ,-1)\cup (5,\infty )$
• D. $(-\infty ,5)$

Answer 1

The correct option is A $(-\infty ,-1)\cup (1,5)$

$\frac{3}{x+1}-\frac{2}{x-1}<0\Rightarrow \frac{x-5}{(x+1)(x-1)}<0$


$\therefore x\in (-\infty ,-1)\cup (1,5)$