The specific conductance of saturated solution of CaF2 is 3.86×10−5 ohm cm−1 and that of water used for solution is 0.15×10−5. The specific conductance of CaF2 alone is:
A
3.71×10−5
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B
4.01×10−5
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C
3.7×10−4
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D
3.86×10−4
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Solution
The correct option is A3.71×10−5
k(CaF2solution)=3.86×10−5Ω−1cm−1
k(watersolution)=0.15×10−5Ω−1cm−1
k(CaF2alone)=?
k(CaF2alone)=k(CaF2solution)−k(Watersolution)
=(3.86−0.15)×10−5Ω−1cm−1
=3.71×10−5Ω−1cm−1
The specific conductance of CaF2 alone is 3.71×10−5Ω−1cm−1