Question

The structure of $I{F}_7$ is:

• A. Octahedral
• B. Pentagonal bipyramidal
• C. Square pyramidal
• D. Trigonal bipyramidal

Answer 1

The correct option is B Pentagonal bipyramidal

In $I{F}_7$,
$\text{Total number of valence electron pairs}=7$
$\text{Total number of bonding electron pairs}=7$
$\text{Total number of lone pairs}=0$
So hybridisation is $s{p}^3{d}^3$.
Shape is pentagonal bipyramidal