The sum of three consecutive multiples of 3 is 72 What is the largest number?
A
21
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B
24
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C
27
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D
36
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Solution
The correct option is B 27 Let the three consecutive multiples of 3 be 3x, 3(x + 1) and 3 ( x + 2), i.e. 3x + 3 and 3x + 6 Given, 3x +3x + 3 + 3x +6 = 72 ⇒ 9x + 9 = 72 ⇒ 9x=63 ⇒ x =7 ∴ Largest multiple of 3 = 3 (x + 2) =3 (7 + 2) =3 x 9 = 27