wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The tangent at a point P on x2a2y2b2=1 cuts one of its directrices in Q. Then PQ subtends at the corresponding focus an angle of

A
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
No worries! We‘ve got your back. Try BYJU‘S free classes today!
D
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
Open in App
Solution

The correct option is D
Equation of the tangent at P(θ)=(a sec θ,b tan θ) as the hyperbola is x sec θay tan θb=1
The tangent cuts the directrix x=aeat Q=(ae,b(sec θe)e tan θ) and focus S = (ae, 0)
We get the product of slopes of ¯¯¯¯¯¯¯¯SP and ¯¯¯¯¯¯¯¯SQ is –1

flag
Suggest Corrections
thumbs-up
1
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Ellipse and Terminologies
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon