The tangent at a point P on x2a2−y2b2=1 cuts one of its directrices in Q. Then PQ subtends at the corresponding focus an angle of
A
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B
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C
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D
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Solution
The correct option is D Equation of the tangent at P(θ)=(asecθ,btanθ) as the hyperbola is xsecθa−ytanθb=1 The tangent cuts the directrix x=aeatQ=(ae,b(secθ−e)etanθ) and focus S = (ae, 0) We get the product of slopes of ¯¯¯¯¯¯¯¯SPand¯¯¯¯¯¯¯¯SQ is –1