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Standard IX

Mathematics

Cuboid

The thickness...

Question

The thickness of a hollow wooden cylinder is $2 c m$ . It is $35 m$ long and its inner radius is $12 c m$ . Find the volume of the wood required to make the cylinder, assuming it is open at either end.

5720 {c m}^{3}

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322000 {c m}^{3}

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472000 {c m}^{3}

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502000 {c m}^{3}

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Solution

The correct option is A $5720 {c m}^{3}$
Volume of a hollow Cylinder $= π (R^{2} - r^{2}) h$
Outer Radius $= 12 + 2 = 14 c m$
Hence, volume of the hollow cylinder $= \frac{22}{7} \times (14^{2} - 12^{2}) \times 3500 = 572000 {c m}^{3}$

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The thickness of a hollow wooden cylinder is 2 cm. It is 35 m long and its inner radius is 12 cm. Find the volume of the wood required to make the cylinder, assuming it is open at either end.

The correct option is A 5720 cm3Volume of a hollow Cylinder =π(R2−r2)hOuter Radius =12+2=14cm Hence, volume of the hollow cylinder =227×(142−122)×3500=572000cm3

The thickness of a hollow wooden cylinder is $2 c m$ . It is $35 m$ long and its inner radius is $12 c m$ . Find the volume of the wood required to make the cylinder, assuming it is open at either end.

The correct option is A $5720 {c m}^{3}$
Volume of a hollow Cylinder $= π (R^{2} - r^{2}) h$
Outer Radius $= 12 + 2 = 14 c m$
Hence, volume of the hollow cylinder $= \frac{22}{7} \times (14^{2} - 12^{2}) \times 3500 = 572000 {c m}^{3}$