Question

The total number of ways in which $6$ persons can be seated at a round table, so that all persons shall not have the same neighbours in any two arrangements.

• A. $60$
• B. $120$
• C. $180$
• D. $360$

Answer 1

The correct option is A $60$

If all persons shall not have the same neighbours in any two arrangements, in this case, anticlockwise and clockwise arrangements should be considered identical.

Hence, the number of ways of arrangements
$=\frac{5!}{2}=60.$