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QUESTION :-4
The two vectors A=^i+2^j+2^kandB=^i^j+n^k are perpendicular to each other, find the value of n

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Solution

Given that,

A=^i+2^j+2^k

B=^i^j+n^k

We know that,

If two vectors​ are perpendicular to each other then their resultant is 0.

Now,

AB=0

(^i+2^j+2^k)(^i^j+n^k)=0

12+2n=0

n=12

Hence, the value of n is 12


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