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Question

The value of (1+w2+2w)3n(1+w2+2w2)3n is equal to

A
Zero
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B
1
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C
w
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D
w2
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Solution

The correct option is A Zero
(1+ω2+2ω)3n(1+ω+2ω2)3n

ω2+ω+1=0
ω2+2ω+1=ω

1+ω+2ω2=ω2
(ω)3n(ω2)3n=(ω3)n(ω3)2n=11=0.

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