The correct option is A 10404(102)^2 = nbsp;(100 + 2)^2. Using the identity: (a+b)^2 = nbsp;(a)^2+2ab+(b)^2, (100 + 2)^2 = nbsp;(100)^2+2(2)(100)+(2)^2 ...

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Standard IX

Mathematics

Algebraic Identities

The value of ...

Question

The value of (102) $^{2}$ is_______.

10404

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9804

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9684

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10604

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Solution

The correct option is A 10404
(102) $^{2}$ = (100 + 2) $^{2}$ .
Using the identity:

(a+b) $^{2}$ = (a) $^{2}$ +2ab+(b) $^{2}$ ,

(100 + 2) $^{2}$ = (100) $^{2}$ +2(2)(100)+(2) $^{2}$
= 10404.

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Similar questions

The value of $(102)^{2} + (98)^{2}$ is:

Question 7

The value of $\frac{10^{22} + 10^{20}}{10^{20}}$ is
(a) 10
(b) $10^{42}$
(c) 101
(d) $10^{22}$

Q. The value of

\frac{10^{22} + 10^{20}}{10^{20}}

is ___.

Q. Find the value of

\frac{10^{22} + 10^{20}}{10^{20}}

Q. Using standard identity, find the value of

102^{2}

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The value of (102)2 is_______.

The correct option is A 10404(102)2 = (100 + 2)2. Using the identity: (a+b)2 = (a)2+2ab+(b)2, (100 + 2)2 = (100)2+2(2)(100)+(2)2 = 10404.

The value of (102) $^{2}$ is_______.

The correct option is A 10404
(102) $^{2}$ = (100 + 2) $^{2}$ .
Using the identity:

(a+b) $^{2}$ = (a) $^{2}$ +2ab+(b) $^{2}$ ,

(100 + 2) $^{2}$ = (100) $^{2}$ +2(2)(100)+(2) $^{2}$
= 10404.