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Question

the value of 2nn!(1.3.5....(2n1)) is


A
(2n)!
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B
(4n)!
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C
(2n)!/n
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D
n!
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Solution

The correct option is A (2n)!
2n(n!)(1,3,5.........(2n1))
(2×2×2......n terms)(1×2×3.......n)(1,3,5,.....(2n1)
(2×4×6.......2n)(1,3,5....(2n1))
[1,2,3,4...2n]
=(2n)!

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