Question

The value of $(3^0-2^0)\times 5^2$ is:

• A. 1
• B. 25
• C. 0
• D. 9

Answer 1

The correct option is C

0

$\because$ For any number a $\ne$ 0, a${}^0$ = 1.

$\therefore 3^0=2^0=1$

$\Rightarrow (3^0-2^0)\times 5^2=(1-1)\times 25=0$