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Question

The value of ∣ ∣a+xyzxa+yzxya+z∣ ∣ is equal to

A
0
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B
a2(a+z+x+y)
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C
a2(z+x+y)
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D
a(a+z+x+y)
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Solution

The correct option is B a2(a+z+x+y)
We have, ∣ ∣a+xyzxa+yzxya+z∣ ∣
Applying C1C1+C2+C3=∣ ∣a+x+y+zyza+x+y+za+yza+x+y+zya+z∣ ∣=(a+x+y+z)∣ ∣1yz1a+yz1ya+z∣ ∣
Applying R2R2R1 and R3R3R1=(a+x+y+z)∣ ∣1yz0a000a∣ ∣=(a+x+y+z)a00a=a2(a+z+x+y)

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