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Question

The value of ∣ ∣xx+yx+2yx+2yxx+yx+yx+2yx∣ ∣ is

(a) 9x2(x+y)
(b) 9y2(x+y)
(c) 3y2(x+y)
(d) 7x2(x+y)

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Solution

(b) We have, ∣ ∣xx+yx+2yx+2yxx+yx+yx+2yx∣ ∣
=∣ ∣ ∣3(x+y)x+yy3(x+y)xy3(x+y)x+2y2y∣ ∣ ∣ [C1C1+C2+C3 and C3C3C2]
=3(x+y)∣ ∣ ∣1(x+y)y1xy1(x+2y)2y∣ ∣ ∣ [taking 3(x+y) common from first column]
=3(x+y)∣ ∣ ∣0y01xy1(x+2y)2y∣ ∣ ∣ [R1R1R2]
Expanding along R1
=3(x+y)[y(2yy)]=3y2.3(x+y)=9y2(x+y)


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