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Question

The value of (1.5)3+(4.7)3+(3.8)33×1.5×4.7×3.8(1.5)2+(4.7)2+(3.8)21.5×4.74.7×3.81.5×3.8 is

A
8
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B
9
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C
10
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D
11
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Solution

The correct option is B 10
a3+b3+c33abca2+b2+c2abbcca

= 12(a+b+c)[(ab)2+(bc)2+(ca)2]12[(ab)2+(bc)2+(ca)2]=(a+b+c)
For a=1.5,b=4.7,c=3.8 value is 1.5+4.7+3.8=10

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