We know that n_C_r=n!/r!(n r)!To calculate the value we put r=nn_C_n=n!/n!(n n)!=n!/n!0!=1 (we know that 0!=1)Hence option(C) is the correct answer and all oth ...

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Standard XII

Mathematics

nth Term of HP

The value of ...

Question

The value of $n_{C_{n}}$ is

$n$

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$0$

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$1$

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$n$ !

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Solution

The correct option is C
$1$

We know that $n_{C_{r}} = \frac{n!}{r! (n-r)!}$
To calculate the value we put $r = n$
${n_{C}}_{n} = \frac{n!}{n!(n-n)!} = \frac{n!}{n!0!} = 1 (weknowthat0!=1)$
Hence option(C) is the correct answer and all other options are incorrect answers.

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The value of nCn is

The correct option is C 1We know that nCr=n!r!(n-r)!To calculate the value we put r=nnCn=n!n!(n-n)!=n!n!0!=1(weknowthat0!=1)Hence option(C) is the correct answer and all other options are incorrect answers.

The value of $n_{C_{n}}$ is

The correct option is C
$1$

We know that $n_{C_{r}} = \frac{n!}{r! (n-r)!}$
To calculate the value we put $r = n$
${n_{C}}_{n} = \frac{n!}{n!(n-n)!} = \frac{n!}{n!0!} = 1 (weknowthat0!=1)$
Hence option(C) is the correct answer and all other options are incorrect answers.