The value of sin−1(sin10)+cot−1(cot(−2))+cos−1(cos(−5)) is
A
3
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B
π−5
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C
3π−13
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D
6π−17
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Solution
The correct option is D6π−17 We know, sin−1(sinx)=3π−x,5π2≤x≤7π2, cot−1(cotx)=x+π,−π<x<0, cos−1(cosx)=x+2π,−2π≤x≤−π ⇒sin−1(sin10)+cot−1(cot(−2))+cos−1(cos(−5)) =3π−10+(−2+π)+(−5+2π) =6π−17