Question

The value of $sin\left(2si{n}^{-1}0.8\right)$ is

• A. $sin{1.2}^{\circ }$
• B. $sin{1.6}^{\circ }$
• C. 0.48
• D. 0.96

Answer 1

The correct option is D

0.96

$sin\left(2si{n}^{-1}0.8\right)Use2si{n}^{-1}x=si{n}^{-1}\left[2x\sqrt{1-x^2}\right]=sin\left[si{n}^{-1}\right(2\times 0.8\sqrt{1-(0.8{)}^2}\left)\right]\Rightarrow sin\left(si{n}^{-1}\right(0.96\left)\right)=0.96$