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Question

The value ofn+1r=1(nk=1kCr1) where r, k, n ϵ N is equal to


A

2n+1

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B

2n+11

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C

2n+12

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D

None of these

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Solution

The correct option is C

2n+12


n+1r=1(nk=1kCr1)n+1r=1(nk=1(k+1CrkCr))n+1r=1(n+1Cr1Cr)=2n+12


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