The value of x for which |x−2|+|x−8|=10 is
3, 7
2, 8
1, 9
0, 10
Given: |x−2|+|x−8|=10
⇒ x−2+x−8=±10
Case 1
x−2+x−8=10
2x−10=10
2x=20
⇒ x=10
Case 2
x−2+x−8=−10
2x−10=−10
2x=0
⇒ x=0
Hence, x can take the values 10,0
Find the value of m for which (2x - 1) is a factor of (8x4+4x3−16x2+10x+m).
If 2x+10=8x, then the value of x is